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3 years ago

Why are scientists concerned about species loss even though extinction is a natural process?

2 answers:

8 0

The extinction of species is a natural process. Over the time, multiple species have become extinct. The process of natural selection ensures that only the most adapted species continue on the Earth. However, when the extinction rate increases then it causes a disbalance. The extinction of one species will cause a sudden rise in the species of its prey and this will cause a disruption. Therefore, the scientists are worried about the loss due to extinction even though it is natural.

velikii [3]3 years ago

5 0

Because, when more species start to become extinct it disrupts the balance of the earth. For instance if spiders became extinct, the numbers of insects would exponentially grow. Which will become a problem for farmers, and more diseases would most likely occur.

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Strontium-90 has a half life of 29 years, how much strontium-90 is left from the Chicago pile reactor that was active around 87

agasfer [191]

Answer:

The answer is below

Explanation:

The half life of a substance is the time required by that substance to reduce to half of its initial value. The half life is calculated using the formula:

$N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N(t)=quantity\ of\ substance \ remaining, N_o=initial\ quantity\\of\ substance, t=time\ and \ t_\frac{1}{2}=half\ life\ of\ substance$

Given that t = 87 years, half life = 29 years, therefore the quantity of strontium-90 left is:

$N(t)=N_o(\frac{1}{2} )^\frac{87}{29} \\\\N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\N(t)=N_o(\frac{1}{2} )^3\\\\N(t)=\frac{1}{8} N_o$

That is one-eight of Strontium 90 would be left after 87 years

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2 years ago

What is the lowest level of organization to include both biotic and abiotic factors?

matrenka [14]

Organisms is the answer to you question

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3 years ago

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Lady_Fox [76]

I think the first option is the answer.

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3 years ago

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In a population with two alleles, B and b, the allele frequency of B=0.59. What would be the frequency of the heterozygotes if t

Levart [38]

Answer:

0.483

Explanation:

The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.

Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1

If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41

The frequency of heterozygous genotype in the population= 2pq

p= frequency of the dominant allele

q= frequency of the recessive allele

So, 2pq= 2 x 0.59 x 0.41 = 0.483

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Harrizon [31]

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3 years ago