Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:

Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Answer:
y =
x + 7
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (2, 8) and (x₂, y₂ ) = (10,12) ← 2 ordered pairs from the table
m =
=
= 
y =
x + c ← is the partial equation
to find c substitute any ordered pair into the partial equation
using (6, 10 ), then
10 = 3 + c ⇒ c = 10 - 3 = 7
y =
x + 7 ← linear equation
A chlorine nucleus will contain: Number of protons Z = 17. Number of protons + neutrons A = 35. Number of neutrons N = 35 - 17 = 18.
Answer:
X= - 12/7 i hope it is helpful have a nice day if you want steps i will show you