Answer:
The area of the dilated rectangle is equal to
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to scale factor squared
Let
z-----> the scale factor
x------> the area of the dilated rectangle
y------> the area of the original rectangle
we have
------> is an enlargement
substitute and solve for x
x = 3
The product of the lengths of segments from the intersection point to the circle is the same for both secants.
... 1×6 = 2×x
... 6/2 = x = 3 . . . . . divide by 2
_____
<em>Comment on secant geometry</em>
Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.
When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,