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Fiesta28 [93]
4 years ago
15

If 30% of John's photographs were perfect, but 210 photographs were not perfect, then how many photographs were there in all?

Mathematics
1 answer:
anyanavicka [17]4 years ago
3 0
If 30% were perfect, 70% were not perfect.  So we know that 70% of the total number of photographs is 210.

p(70/100)=210  multiply both sides by 100

70p=21000  divide both sides by 70

p=300

So there are 300 photographs in all.
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(6x - 3) - (-3x + 2)
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Answer:

Step-by-step explanation:

Simplifying

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Reorder the terms:

-3 + 6x = (3x + -2)

Reorder the terms:

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Remove parenthesis around (-2 + 3x)

-3 + 6x = -2 + 3x

Solving

-3 + 6x = -2 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

-3 + 6x + -3x = -2 + 3x + -3x

Combine like terms: 6x + -3x = 3x

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Combine like terms: 3x + -3x = 0

-3 + 3x = -2 + 0

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Add '3' to each side of the equation.

-3 + 3 + 3x = -2 + 3

Combine like terms: -3 + 3 = 0

0 + 3x = -2 + 3

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Simplifying

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3 years ago
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