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Elza [17]
3 years ago
12

Who will go out with me? a:William b:Oscar c:oliver

Mathematics
2 answers:
Mademuasel [1]3 years ago
4 0
Wiliammmmmmmmmmmmmmm
ANEK [815]3 years ago
3 0

Answer:

William

Step-by-step explanation:

You might be interested in
What is 2.25 as a improper fraction
navik [9.2K]

~ Convert the decimal number to a fraction by placing the decimal number over a power of ten.

~ Next, add the whole number to the left of the decimal.

2 25/100

~ Reduce the fractional part of the mixed number.

2 1/4

Answer: 2 1/4

Hope this helps :)

3 0
3 years ago
Read 2 more answers
(PERSON WHO ANSWERS WILL BE MARKED BRAINLIEST) Timothy has begun selling copies of his first work of art. In the first year, he
tresset_1 [31]
Y = 40
Since, 
1st year = 200 
2nd year= 200 + 40 =240
3rd year = 240 + 40 = 280
4th year = 280 + 40 = 320
5th year = 320 + 40 =360
6th year = 360 + 40 = 400.
So, basically all you have to do is add 40!
Therefore, the answer is y = 40 Hope this helped! :)

6 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
Question 3 (1 point)
solong [7]

Answer:

let's do it

4 * 8 - 4 *7 =?

32-28=4

7 0
3 years ago
A binomial has been partially factored, as shown below:
sesenic [268]
Answer: x-6

Explanation: x^2 is a DOTS, or difference of two squares. 36 is a perfect square and x^2 is a perfect square, and you are finding the difference. Therefore, you can do (x+6)(x-6). This works with any number. If there was x^2-16, it could be factored to (x+4)(x-4)
3 0
3 years ago
Read 2 more answers
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