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3 years ago

∆ABC ~ ∆DEF. If ∠A=35° and ∠E=55°, what is the measure of ∠C?

Mathematics

1 answer:

madam [21]3 years ago

7 0

Answer:

90°

Step-by-step explanation:

ABC ~ DEF so that means E = B. A triangle has to add up to 180° so that means 180-35-55=90

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Convert the following into fractions in their simplest form

sladkih [1.3K]

Answer:

1/10

13/100

4/5

12/25

3/10

63/100

3/5

51/200

2/9

5/11

To prove the last 2 recurring ones:

0.222222... = x

10x = 10 * 0.22222... = 2.222222....

Notice how the decimal part of 10x is the same as for x:

10x - x = 2.2222222... - 0.222222... = 2

10x - x = 9x = 2

x = 2/9

Same procedure for the other one but times by 100 instead:

x = 0.454545...

100x = 45.454545...

100x - x = 45.454545... - 0.454545... = 45

100x - x = 99x = 45

x = 45/99 = 5/11

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3 years ago

Use the drop-down menus to choose steps in order to correctly solve 1+2b−13=12−4b−2b for b. Pls help

MrMuchimi

b=3

I found this out by subtracting and adding on both sides.

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3 years ago

Read 2 more answers

The sum of 2 consecutive whole numbers is 206. What are the 2 numbers

Anni [7]

Answer:

102.5, 103.5

Step-by-step explanation:

a+a+1=206

2a+1=206

2a=205

a=102.5

103.5

I think there is a bug here. They can't be whole numbers.

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3 years ago

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A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

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3 years ago

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Rufina [12.5K]

1/2 -3/6 is equal to 0 because 1/2 is equal to 1/2

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3 years ago