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alisha [4.7K]
3 years ago
12

What would be 2 + 7x + 3 − 5x − 1 = ______ plz help

Mathematics
2 answers:
horsena [70]3 years ago
8 0

Answer:

4 +2x

2(2+x)

Step-by-step explanation:

2 + 7x + 3 − 5x − 1

Combine like terms

2+3-1   +7x-5x

4 +2x

We could also factor out a 2

2(2+x)

labwork [276]3 years ago
7 0
B :)))))))))))))))))))))))))))))))))))))))))))))((
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The answer is 1.5 i think
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I conclude from the information given that he is just very lucky. I believe he is lucky, because it is very hard to perform tric
VikaD [51]

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I believe that the owner of the dice is actually not lucky. There are people who practice throwing dice in a controlled way in order to get a specific side of the dice. If he practices his dice throwing a lot, then he would have a much higher chance of winning at a game of dice.

Step-by-step explanation:

Since you said he was lucky, I decided to make an answer saying that he wasn't lucky so you can choose between both of them. Your answer was good as well.

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2 years ago
Simplify. Consider all cases. |14−(x−6)|
yanalaym [24]

Answer:

20-x; -20+x; -20-x; 20+x

Step-by-step explanation:

|14-x+6|

|20-x|

20-x; -20+x; -20-x; 20+x

4 0
2 years ago
Read 2 more answers
Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more
Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1)         (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2)        (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3)        (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c)  + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

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3 years ago
Find ? And the appropriate equation to do so
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I would say 25 or 30 it looks like25

Step-by-step explanation:

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