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Minchanka [31]
4 years ago
5

10 have volunteered to help with the preparations for a party. How many ways can Susan assign someone to buy​ beverages, someone

to arrange for​ food, and someone to send the​ invitations? Assume that no person does two jobs.
Mathematics
1 answer:
Lesechka [4]4 years ago
5 0

Answer:

The answer is 720 ways.

Step-by-step explanation:

Total friends who volunteered = 10

Total number of jobs that have to be done = 3

Here order matters, so it is a permutation question.

We can use the formula nPr.

= \frac{10!}{7!}

= 720 ways.

The second way to solve this is:

Susan can choose the first person to do a job in 10 ways

Then the second job can be done in 9 ways and the third in 8 ways.

Total becomes = 10\times9\times8=720 ways

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I used
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