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Minchanka [31]
3 years ago
5

10 have volunteered to help with the preparations for a party. How many ways can Susan assign someone to buy​ beverages, someone

to arrange for​ food, and someone to send the​ invitations? Assume that no person does two jobs.
Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

The answer is 720 ways.

Step-by-step explanation:

Total friends who volunteered = 10

Total number of jobs that have to be done = 3

Here order matters, so it is a permutation question.

We can use the formula nPr.

= \frac{10!}{7!}

= 720 ways.

The second way to solve this is:

Susan can choose the first person to do a job in 10 ways

Then the second job can be done in 9 ways and the third in 8 ways.

Total becomes = 10\times9\times8=720 ways

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First, work out how much you need to add to A's x and y coordinates in order to get to point B from point A.

So (using Ax to mean x-coordinate of A, Ay the y-coordinate of A, etc):
x-difference = Bx - Ax = 3 - (-3) = 3 + 3 = 6
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Now, if the point divides the segment AB in the ratio 2:3, then it is 2/(2+3) of the way along the line AB.

i.e. it is 2/5 of the way along the line AB.

We therefore need to add 2/5 of the x- and y-differences to point A to get point p:
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3 years ago
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