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andreev551 [17]
3 years ago
15

The triangles below are similar

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:

Step-by-sAnswer:

\triangle CBA \sim\triangle EFD

Step-by-step explanation:

\triangle CBA \sim\triangle EFD is the appropriate similarity statement.tep explanation:

hope it helps BC i don't know about it my cousin helped me and he was laughing so sorry if it doesn't help :)

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PQ is a diameter of a circle with centre If angle PQR=55 ,SPR=25 and angle PQM=50
tigry1 [53]

Answer:

m∠QPR = 35°         m∠QPM =40°       m∠PRS = 30°

Step-by-step explanation:

ΔPRQ is a right triangle with right angle at R.  So m∠QPR = 90 - 55 = 35

ΔQPM is a right triangle with right angle at M.  So m∠QPM = 90 - 40 = 40

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Therefore, m∠PRS = 60/2 = 30

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5 0
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Step-by-step explanation:

S=9

E=2,6,8,10,12

Both 4

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