If the bisector of ST intersects at point N, and ST is 8in., what is NT? 4in., 12in., 16in., or 6in.
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The zeros are at x=8 and x=2. The x-coordinate of the vertex is halfway between, at
x = (8+2)/2 = 5
The y-coordinate of the vertex is f(5) = (5-8)(5-2) = -9
The vertex of f(x) is (5, -9).
x = (8+2)/2 = 5
The y-coordinate of the vertex is f(5) = (5-8)(5-2) = -9
The vertex of f(x) is (5, -9).