Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Answer:
Step-by-step explanation:
1 × 99 = 99. 3 × 33 = 99. 9 × 11 = 99
-1400 + 800 - 350 = - 950 meters
Let's give some distances
100 up 100 flat 100 down meters
then return 100 up 100 flat 100 down
time required (distance/rate = time ) 200/100 + 200/120 + 200 / 150 = 5 hr
distance 600
distance / time = average speed = 600/5 = 120 m/s
