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scoundrel [369]
2 years ago
9

WILL MARK BRAINLIEST Give the reason why tho following is not a polynomial x^2-3x^-1+5

Mathematics
1 answer:
steposvetlana [31]2 years ago
7 0

Answer:

The three is negative

Step-by-step explanation:

A polynomial cannot have a variable in the denominator or a negative exponent so the reasoning is Because the three is negative

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You deposit $1,200.00 into an account and in three years of simple interest you have $1,380. What interest rate are you receivin
Tcecarenko [31]
Since simple interest doesn't involve compounding, the same amount gets added on every year. So, the equation for the simple interest received is I = Prt, where I is the total interest, P is the original deposit (or "principal"), r is the interest rate, and t is the time passed in years.

Plugging in our values, we can solve for the interest rate:

I = Prt
\$1380 - \$1200 = (\$1200)(r)(3 years)
\$180 = (\$1200)(r)(3 years)
r = .05 = \bf 5 \%
6 0
3 years ago
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
2 years ago
HELP!! Plzz I’m in a test and I really need help
In-s [12.5K]

Answer:

i wish i could help you

Step-by-step explanation:

5 0
3 years ago
What is the area of the figure?
mrs_skeptik [129]
We see that the shape is made up of 2 shapes:
trapezoid and triangle
(trapezoid is on top of upside down triangle)

area of trapezoid=(1/2)(b1+b2)(h)
area of traignel=(1/2)(b)(h)

area of trapezoid
b1=14
b2=18
h= ok so total height=17 and 12 is taken up by triangle os therefor h=17-12=5

A=(1/2)(14+18)(5)
A=(1/2)(32)(5)
A=(16)(5)
A=(80)




now area of triangle
H=12
B=18
A=(1/2)(18)(12)
A=(9)(12)
A=108

add
80+108=188


total area=188mm^2
5 0
3 years ago
If the nth term of a sequence is 7x5n-1, find the 2nd term.
lawyer [7]
7×5(2)-1=
7×10-1=69
nth term= 69.
maybe.
3 0
2 years ago
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