It could be The 4.0 cm would be the base and 2.8cm would be the length upwards
V=(4/3)pir^3
r=12
V=(4/3)pi12^3
V=(4/3)pi1728
V=2304pi in^3
Answer:
45cm or 9cm are all the possible lengths
First, that looks like Pearson and if it is, I'm so sorry for you.
Secondly, I think this answer is correct.