So, i would use the add the two equation method, so add those to get:
2e=-4
e=-2
then plug in e to get d, so d+-2=1
d=3
plug into the other one to make sure
-3+-2=-5
so it would be (3,-2)
let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer: k ≤ -4 or k ≥ 
<u>Explanation:</u>
| 3k + 4 | ≥ 8
3k + 4 ≥ 8 or 3k + 4 ≤ -8
<u> -4</u> <u> -4 </u> <u> -4</u> <u>-4 </u>
3k ≥ 4 or 3k ≤ -12
<u>÷3 </u> <u>÷3 </u> <u> ÷3 </u> <u>÷3 </u>
k ≥ or k ≤ -4
0.78 converted to a percent would be 78%
Answer:
Step-by-step explanation:
