Answer:
The change in temperature per minute for the sample, dT/dt is 71.
°C/min
Step-by-step explanation:
The given parameters of the question are;
The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)
The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min
Given that both dQ/dT and dQ/dt are known, we have;


Therefore, we get;


For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

CD is called the middle base and is equal to :(AB + EF)/2
CD = <span>(AB + EF)/2
4x = [(x</span>²+10) + (8-x)]/2
8x = x²+10+8-x
8x= x²-x+18
x²-9x+18 = 0
x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b<span>²-4.a.c)]/2a
x'= 6 and x" = 3, So we have2 values of x</span>
145. u take 180 subtract 35. It will gives u 145
9514 1404 393
Answer:
- Ram -- ₹1200
- Kalpana -- ₹800
Step-by-step explanation:
Their age total is 15+10=25, so Ram will get 15/25 = 0.6 of the total. Kalpana will get the remaining 0.4 of the total.
Ram receives 0.6 × ₹2000 = ₹1200
Kalpana receives 0.4 × ₹2000 = ₹800