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lara [203]
3 years ago
15

Can you help me with this!!!!!!!!!

Mathematics
1 answer:
alexira [117]3 years ago
4 0

a. The first variable is x and the second variable is y.

b. The equations are x+y=12 and x-y=8.

Step-by-step explanation:

Step 1:

The first step is to define the variables. The variables can be any two symbols, letters, characters, etc.

Here let the first variable be x and the let the second variable be y.

So the variables are defined as x and y.

Step 2:

The sum of the given variables is 12.

The first variable + the second variable = 12,

x+y=12.

The difference between the two variables is 4.

The first variable - the second variable = 4.

x-y=4.

Step 3:

If we add both the equations we get, 2x =16, x= 8 and y=4.

x = 8 and y = 4.

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Use the distance formula to find distance between two points. Need help on this ASAP.
astra-53 [7]

Answer:

a) 20 units

b) 2 √10 units

c) 2 √17 units

Step-by-step explanation:

The distance formula is;

D = √(y2-y1)^2 + (x2-x1)^2

a) D = √(-7-9)^2 + (-7-5)^2

D = √256 + 144

D = √400

D = 20

b) D = √(10-8)^2 + (9-2)^2

D = √(2)^2 + 6^2

D = √4 + 36)

D = √40

D = 2 √10 units

c) D = √(1 + 7)^2 + (-8+10)^2

D = √(64 + 4)

D = √68

D = 2 √17 units

3 0
2 years ago
5) Adrianna's quilt has this pattern: What is the pattern unit for the rug ? What is the next shape? answer:​
CaHeK987 [17]

Answer:

square

Step-by-step explanation:

5 0
2 years ago
Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%
Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline  is required for  4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6              :    x

98        : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6              :    x

96        : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For  4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline =  3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of  4 gallons= 0.08 gallons of motor oil.

6 0
2 years ago
What is the value of x<br> if 2x+4=3
kolezko [41]

2x + 4  = 3 \\  \\ 2x = 3 - 4 \\  \\ 2x =  - 1 \\  \\ x = -   \frac{1}{2}

# Bora 7#

5 0
2 years ago
Fred and Frank play a game. Fred picks an even number X and asks Frank to add all even numbers between 0 and X (inclusive) as fa
TiliK225 [7]

Answer:

The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2

The rule of arithmetic sequence = a + d(n - 1)

Where a is the first term and n is the number of terms

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So, we need to find n at the last term which is X

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∴ n = X/2 + 1

The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)

Substitute with a and d and X

So, the sum = (n/2) * (2*0 + (n−1)*2)

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                   = n(n-1)

                   = (X/2 + 1) * (X/2)

                   = X/2 by (X/2 + 1)

So, The quick way to add all even numbers between 0 and X always works.

8 0
3 years ago
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