Answer:
50°
Step-by-step explanation:
As usual, the diagram is not drawn to scale.
The chord divides the circle into two arcs that have a sum of 360°. If we let "a" represent the measure of the smaller arc, then we have ...
a + (a+160°) = 360°
2a = 200° . . . . . . . . . . . subtract 160°
a = 100°
The measure of the angle at A is 1/2 the measure of the subtended arc:
acute ∠A = a/2 = (1/2)·100° = 50°
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<em>Comment on this geometry</em>
Consider a different inscribed angle, one with vertex V on the circle and subtending the same short arc subtended by chord AB. Then you know that the angle at V is half the measure of arc AB. This is still true as point V approaches (and becomes) point A on the circle. When V becomes A, segment VA becomes tangent line <em>l</em>, and you have the geometry shown here.
Example 1:
The pros of Orthographic is that they can show hidden details and all of the connecting parts, they can be annotated to display material and finishes. The pros of Isometric projection is that they dont need many views and it gives accuracy, cons are is created a unorginized apperance by the lack of foreshortening, I would choose Isometric projection because it shows the size of the figure.
Example 2:
Orthographic projection is a good option for showing lots of detail and small things. The limitation is that with all of that detail, they can become quite messy and hard to understand to someone new to them. However, that is one of the pros of Isometric projection. It gives easy detail and is just as good as an Orthographic. Personally, I find Isometric projections easier to interpret.
Answer:
150.72
Step-by-step explanation:
3² × 3.14 × 6 - 1² × 3.14 × 6 = (3² - 1²) × 3.14 × 6 = 150.72
Observe the given figure.
Here, angle T and R are the inscribed angles.
And sum of inscribed angles is half of measure of intercepted arcs.
Since, the measure of intercepted arcs is 360 degrees.
Therefore, 

Hence, the sum of the two angles is 180 degrees.
Therefore, these are the supplementary angles.
Therefore, angle T and angle R are supplementary angles.
Hence, proved.