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3 years ago

3.6399; thousandths round it

Mathematics

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

3.6399 = 3.640

Step-by-step explanation:

$3.6399\\1\:2\:3$

Rounding to nearest thousandth means rounding to 3 decimal place

(0 to 4) =round down

(5 to 9)= round up

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4y+13=37 a 6 b 24 c 20 d 4

fiasKO [112]

A) 6
Replace the y with 6
4(6)+13=37
Multiply
24+13=37
Add
37=37
I hope this helps :)
If you have any questions about my answer please feel free to ask:)

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2 years ago

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spayn [35]

I believe the answer is A

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2 years ago

Find the volume of a cone with a height of 12m and a base diameter of 10m. Use the value 3.14 for π, and do not do any rounding.

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3 years ago

Help me with the work

Tpy6a [65]

Answer:

Option B k > 0

Step-by-step explanation:

we know that

Observing the graph

The slope of the line is positive

The y-intercept is negative

we have

$3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)$

The slope of the line is equal to

$m=\frac{1}{3}[5k+2]$

Remember that the slope must be positive

$5k+2> 0\\ \\k > -\frac{2}{5}$

The value of k is greater than -2/5

Analyze the y-intercept

$(2-\frac{4}{3}k) < 0\\ \\ 2 < \frac{4}{3}k\\ \\1.5 < k\\ \\k > 1.5$

1.5 is greater than zero

the solution for k is the interval ------> (1.5,∞)

therefore

must be true

k > 0

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3 years ago

NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

$y = 3x$

We want everything below this line (line included), so the first inequality is

$y \leq 3x$

The line between the origin and B is

$y = \dfrac{1}{3}x$

We want everything above this line (line included), so the second inequality is

$y \geq \dfrac{1}{3}x$

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

$A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}$

Which means

$A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}$

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

$B:\ 1$

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0

3 years ago

3.6399; thousandths round it ​

3.6399; thousandths round it