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grin007 [14]
3 years ago
12

An Elevator descends into a mine shaft at the rate of 5m/min. If the descend starts from 15m above the ground, how long will it

take to reach 350m deep from the ground?
Mathematics
1 answer:
zhenek [66]3 years ago
5 0
First of all, assuming that the "ground level" is 0; 

The lift is not starting from 0, so we also need to account for the extra 15 meters above the ground the lift is. 

The total distance the lift would cover in the downward direction: 15+350=365m

Now, you know that the lift covers 5 m/min

Therefore, 5x=365 (ignoring units because they can complicate things) 

x=365/5 
x=73 minutes 

Therefore, they would take 73 minutes to reach 350 m deep into the ground with a starting position 15 m above the ground. 

Hope I helped :) 
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Answer:

7

Step-by-step explanation:

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24 * 24 * 1 = 576 ft³

Additional 20 %

By rule of three      

if     576       ⇒    100

        x??      ⇒     20           x = 115,2

And there are 2 slabs, the total volume of concrete is:

Q(t)  = 2* (576 + 115,2 )      Q(t)  =  1382,4 ft³   (1)

If the truck can carry a maximum of 8 yd³, as 1 ft³  = 0,037 yd³

then a truck can carry a maximum of

8/ 0,037   =  216,21 ft³

Now the total quantity is 1382,4

Then  

1382,4/216,21        =  6,39

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3 years ago
What fraction of one day is 36 mins​
Nezavi [6.7K]

Answer:

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3 0
1 year ago
Can someone show me the steps to doing this ?
VMariaS [17]
U're goal is to get k alone.
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3 0
3 years ago
Describe and correct the error a student made in finding the midpoint cd with c(-4,5) and d(-1,-4).
Gnesinka [82]

Answer:

Step-by-step explanation:

The formula for finding the midpoint of two coordinates is expressed as;

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Given the coordinates c(-4,5) and d(-1,-4), x1 = -4, y1 = 5, x2 = -1 and y2 = -4.

For the X coordinate of the midpoint

X = x1+x2/2

X = -4+(-1)/2

X = -4-1/2

X = -5/2

X = -2.5

Similarly for Y:

Y = y1+y2/2

Y = 5+(-4)/2

Y = 5-4/2

Y = 1/2

Y = 0.5

Hence the midpoint coordinate of C(-4,5) and D (-1,-4) is (-2.5, 0.5)

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3 years ago
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Answer:

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