Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
Step-by-step explanation:
(-2x-3)(4x+5) = -(2x+3)(4x+5) = -(8x^2+12x+10x+15) = -8x^2 - 22x - 15
Leading coefficient is -8
Answer:
A, C, E
Step-by-step explanation:
It does represent a direct variation.
Direct variation: y = kx
y varies directly with x
Your equation 2y = 5x + 1 is in the form of y = kx but we need to divide out the 2 from 2y so we have the following
2y = 5x + 1
2y / 2 = 5 x/ 2 + 1/2
y = 5x / 2 + 1/2
y = kx
k = 5/2
k = constant of variation = 5/2
