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kolbaska11 [484]
3 years ago
6

The Price of kiwis can be deterrent by the equation P=1.15n where p is the price and n is the number of kiwis. What is the const

ant of proportionality (unit rate)?
Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

1.15

Step-by-step explanation:

P/n = 1.15

Price is 1.15 per kiwi

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The athletic departments at 10 randomly selected U.S. universities were asked by the Equal Employment Opportunity Commission to
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Answer:

<em>5.5</em>

Step-by-step explanation:

Given the set of data

5, 4, 2, 1, 1, 2, 10, 2, 3, 5.

The average of the least and the greatest value is known as the midrange

The formula for calculating the midrange is expressed as shown:

Midrange = (Greatest value + Least value)/2

Given

Greatest value = 10

Least value = 1

Midrange = 10+1/2

Midrange = 11/2

Midrange = 5.5

<em>Hence the midrange of the data is 5.5</em>

8 0
2 years ago
How do you solve -12n^2-11n=-15<br> Solve for n
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Explanation:

N= 3/4 or n= -5/3
8 0
3 years ago
I don't know how to do this!!​
saw5 [17]
3x-1=77 (due to exterior alternate angle)
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6 0
2 years ago
on the first day of the year, you have $700 in your bank account. you spend $35 per week. your friend starts the year with $450
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5weeks
<span>Good! Since you want to find when both of you have the same amount of money, you can set the two expressions representing the money equal to each other. This gives the equation $700 – $35 per week • weeks = $450 + $15 per week • weeks. Solving the equation, you find that you will have the same amount of money in 5 weeks.</span>
7 0
3 years ago
Read 2 more answers
Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen
kati45 [8]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q      ∼P     ∼Q     P⇔ Q    ∼P ∨ Q     ∼Q ∨ P        (∼P ∨ Q)∧(∼Q ∨ P)

T     T         F        F             T            T                   T                       T

T     F         F        T             F             F                   T                       F

F     T         T        F             F            T                   F                       F

F     F         T        T             T            T                   T                       T

Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.

Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).

8 0
3 years ago
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