Complete question :
A pair of $36 jeans were on sale at Jim's Jeans for 1/3 off. The same pair of jeans were $42 at David's Denims. The jeans were on sale for 2/3 off.
A.) which store had the better buy
B.) how much will you pay at the store that has the better buy
Answer:
A.)David's denim has the better buy
B.) $14
Step-by-step explanation:
Jim's Jean store :
Cost of Jean = $36
Discount = 1/3 off
Discounted cost = $36 - (1/3 * $36)
Discounted cost = $36 - $12 = $24
David's Denim:
Cost of Jean = $42
Discount = 2/3 off
Discounted cost = $42 - (2/3 * $42)
Discounted cost = $42 - $28 = $14
David's denim has the better buy with a discounted price lower than the discounted price at Jim's store.
Cost at store with the better buy is $14
If the lines cross, there is a solution , which means that there is a y and x value which satisfies both equations.
since both the equations start with x+y they shoulddd have the same answer if they had crossed. we can tell straight away these lines do not cross because 6=/=4 6 doesnt equal 4. therefore no solution.
TIP: for the future, if they had crossed, you can use simultaneous equations to find x and y to see if they work in each equation and find a solution ( since they are straight lines there will only be 1 solution, unless they are literally the same line in which case then then they are ALWAYS on top of each other and always have the same values)
(x² + 4x - 45)/(x² + 10x + 9)
<span>
Numerator = N = x² + 4x - 45 </span>
= x² + 9x - 5x - 45
= (x² + 9x) - (5x + 45)
= x(x + 9) - 5(x + 9)
= (x + 9)(x - 5)
<span>
Denominator = D = x² + 10x + 9 </span>
= x² + x + 9x + 9
= (x² + x) + (9x + 9)
= x(x + 1) + 9(x + 1)
= (x + 1)(x + 9)
<span>
Hence, the given expr. = N/D </span>
= {(x + 9)(x - 5)}/{(x + 1)(x + 9)
= (x - 5)/(x + 1)
<span>
Restrictions : x ≠ - 1, x = 5 </span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Rotation about a point does not change any dimensions. C'D' = CD = 2.8 units.
Are u looking for there total radius or what I don’t know what you are looking for
