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ss7ja [257]
2 years ago
9

Why is y=-2x considered a function?

Mathematics
1 answer:
finlep [7]2 years ago
6 0

Yes

Step-by-step explanation:

its a direct-variation function

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The coordinates of Trapezoid EFGH are E(8, 8), F(8,10), G(1, 6), and H(4, 1). The image of EFGH under dilation is E’F’G’H’.
Sergeu [11.5K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below are the choices:

A) (2, 6) 
<span>B) (4, 6) </span>
<span>C) (2, 5) </span>
<span>D) (4, 5)
</span>
The answer should be: (4, 5)
<span>E = (8, 8) -----> E' = (4, 4) = (8/2, 8/2) 
</span><span>F = (8, 10) -----> F' = (8/2, 10/2) = (4, 5)</span>
5 0
3 years ago
Find the slope \mathrm{m}m of the line in the graph below. ​ ​ \mathrm{m} =m=
yulyashka [42]

Answer:

m=4 or m=\frac{4}{1}

Step-by-step explanation:

To find slope we use the slope formula

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }

Two points on the line we can classify are (3,4) and (4,8)

5 0
2 years ago
The cost of pating a circluar traffic sign is $3.50 per square inches
Juli2301 [7.4K]
First you would have to find how many inches the sign is, then you would find the radius and then multiply that by 3.50
3 0
3 years ago
Peter planter has 7 rows of pineapple plants with 8 plants in each row. how many pineapple plants does he have?​
katrin [286]

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56

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
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