Ask question

Ask question

All categories

3 years ago

5

A _____________________ is a list of things where each thing appears only once and order matters.

1 answer:

diamong [38]3 years ago

4 0

I think is called sequence

You might be interested in

Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4

crimeas [40]

We have been given an expression $\left( 4^{-2} \cdot 4^{-3} \right)^{3}$ . We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, $a^m\cdot a^n=a^{m+n}$ , we cab rewrite our given expression as:

$\left( 4^{-2+(-3)} \right)^{3}$

$\left( 4^{-5} \right)^{3}$

Now we will use exponent property $(a^m)^n=a^{m\cdot n}$ to further simplify our expression.

$\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}$

$\left( 4^{-5} \right)^{3}= 4^{-15}$

Therefore, Chris made mistake in step 2.

8 0

3 years ago

7/√10-√3<br> plss faast very urgent

Bogdan [553]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Here's the solution :

$\dfrac{7}{ \sqrt{10 } - \sqrt{ 3} }$

$\dfrac{7}{ \sqrt{10} - \sqrt{ 3} } \times \dfrac{ \sqrt{10} + \sqrt{3} }{ \sqrt{10} + \sqrt{3} }$

$\dfrac{7( \sqrt{10} + \sqrt{3} )}{( \sqrt{ 10}) {}^{2} - ( \sqrt{ {3}})^{2} }$

$\dfrac{7 (\sqrt{10} + \sqrt{3}) }{10 - 3}$

$\dfrac{7( \sqrt{10} + \sqrt{3} )}{7}$

$\sqrt{10} + \sqrt{3}$

6 0

2 years ago

Read 2 more answers

Whats 100 times 1,002 times 54

pychu [463]

5410800 is your answer.

7 0

3 years ago

Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the r

Mademuasel [1]

New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4) = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4) = C' (2 + 7 , 4 -1 )= C' (9,3)
<span>D(2, 2) D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)</span><span>

</span>

8 0

2 years ago

Does anyone know the answer to this? Algebra 2

natulia [17]

Answer:

Step-by-step explanation:

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

If, sinθ = - $\frac{1}{2}$ and π < θ < $\frac{3\pi }{2}$

Since, sinθ is negative, angle θ will be in IIIrd quadrant.

And the measure of angle θ will be (180° + 30°)

θ = 210°

It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.

Therefore, cos(210°) = $-\frac{\sqrt{3} }{2}$

tan(210°) = $\frac{1}{\sqrt{3} }$

csc(210°) = $-\frac{1}{2}$

sec(210°) = $-\frac{2}{\sqrt{3} }$

cot(210°) = √3

3 0

3 years ago