Your answer would be 3.4
Anything under 5 it stays the same and anything over 5 it goes up one
Answer:
The first one is -1/2
the second one is x+2y-27=0
Answer:
8
Those little "sticks" are called absolute value.
For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.
Thus, it doesn't matter if the number is positive or negative. As it only counts its <u>d</u><u>i</u><u>s</u><u>t</u><u>a</u><u>n</u><u>c</u><u>e</u><u> </u><u>f</u><u>r</u><u>o</u><u>m</u><u> </u><u>0</u><u>,</u><u> </u><u>o</u><u>n</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>l</u><u>i</u><u>n</u><u>e</u><u>.</u>
I hope it helps.
Answer:
Step-by-step explanation:
y ∝ x^2
Introducing the proportionality constant, we have
y = kx^2
Given : y= 18 when x = 3
substitute the given values in order to get the constant
i.e 18 = k x 3^2
18 = 9k
k = 2
therefore the formula connecting x and y
⇒ y = 2x^2
To find y if x is 4, just substitute x = 4 into the formula connecting x and y
i.e y = 2 x 4^2
= 2 x 16
= 32
Since all four terms don't have a common factor we will group them in pairs with common factors.
6uv - 3v^3 + 4u - 2v^2
6uv + 4u - 3v^3 - 2v^2
Take out 2u from the first two terms and -v^2 from the last two terms. The goal is to have a common factor once we take out the GCF's.
2u( 3v + 2) - v^2(3v + 2)
Now we have two terms:
[2u(3v+2)] + [-v^2(3v+2)]
These two terms have a GCF of (3v + 2). Take that out:
(3v + 2)(2u - v^2)