What is the meaning of the unknown factor and quotient

Mathematics

1 answer:

konstantin123 [22]3 years ago

5 0

Unknown factor is multiplication and then quotient is division

You might be interested in

An ostrich can run at a rate of 50 miles in 60 minutes.

defon

So 50 miles/60 minutes and you basically just convert it
you want to divided by 10 so you will get
5miles/6minutes
and then multiply both by 3 and you will get 18

so it takes 18 minutes

7 0

3 years ago

Solve . 3/27 = w/54

WINSTONCH [101]

$\frac{3}{27}=\frac{w}{54}$ Multiply 54 to both sides to get "w" by itself

$(54)\frac{3}{27}=\frac{w}{54}(54)$

$\frac{162}{27} =w$

6 = w

6 0

3 years ago

Read 2 more answers

Simplify 2x - 3(-4x + 2 )

OleMash [197]

8 0

3 years ago

Read 2 more answers

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$