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4 years ago

Ali's dog weighs 8 times as much as her cat together, the two cats weigh 54 pounds. how much does Ali's dog weigh

Mathematics

2 answers:

solniwko [45]4 years ago

6 0

Ali's dog weight 864

horrorfan [7]4 years ago

3 0

Ali's dog weighs 864.

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Let C be between D and E . Use the segment Addition Postulate to solve for x.

lys-0071 [83]

Answer:

$x = 18$

Step-by-step explanation:

Given

$DC=14$

$CE=x$

$DE=32$

Required

Find x

Because C is between D and E;

$DE = DC + CE$

Substitute values for each;

$32 = 14 + x$

Collect Like Terms

$x = 32 - 14$

$x = 18$

8 0

3 years ago

Convert to a fraction 12 3\100

sashaice [31]

Answer:

1203/100

Step-by-step explanation:

12 times 100 equals 1200 plus three equals 1203/100

8 0

3 years ago

Please help me solve this problem ASAP

MArishka [77]

Use the pythagorean theorem formula: a^2 + b^2 = c^2
c is the longest side of a triangle.
Plug 14 and 11 into a and b and find c.

14^2 + 11^2 = c^2
196+121=317
Square root it.
and you get square root of 317

6 0

3 years ago

Solve and show work 6+(-6)^2-(-9)

Tcecarenko [31]

The answer is 51
6+36- (-9)
42- (-9)

8 0

4 years ago

A person participates in a state lottery by selecting six numbers from 1 through 51. If the six numbers match the six drawn by t

Licemer1 [7]

There are

$\dbinom{51}6=\dfrac{51!}{6!(51-6)!}=18,009,460$

total ways to draw any 6 numbers from the range 1 to 51, regardless of order.

Given 6 selected numbers that match those drawn by the lottery, there are

$6!=720$

ways of rearranging them. So the probability of winning 1st prize is

$\dfrac{720}{18,009,460}=\dfrac{36}{900,473}\approx0.0000399790$

Next, given 6 selected numbers of which 5 match those drawn by the lottery, there are

$5!=120$

ways of rearranging those 5 matching numbers. There are 46 remaining numbers that didn't get drawn, so the probability of winning 2nd prize is

$\dfrac{46\cdot120}{18,009,460}=\dfrac{12}{39,151}\approx0.0003065$

7 0

4 years ago