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LekaFEV [45]
3 years ago
13

Use the Remainder Theorem to evaluate f(10) for: f(x) = 2x^3 – 14x^2 - 56x - 40

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0

Step-by-step explanation:

Since we are told that 10 is a zero,

(x−10) must be a factor:

F(x)=2x3−14x2−56x−40

F(x)=(x−10) (2x2+6x+4)

F(x)=2(x−10)(x2+3x+2)

F(x)=2(x−10)(x+2)(x+1)

So the other two zeros are

x = -2 and x= −1

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Step-by-step explanation:

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2 years ago
Read 2 more answers
Find the solutions <br> x^2=16x-28
ioda
Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to -16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative

(x-14)(x-2)=0
set each to zero
x-14=0
x=14

x-2=0
x=2

x=2 and 14
7 0
3 years ago
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