Answer:
Step-by-step explanation:
Now we cal calculate the quantities requested
Just find the one that goes in a straight line and starts at the middle
Answer:
(AD)=SQRT(20n^2+34-4n)
Step-by-step explanation:
let the point of intersection between AC and DB be O. Then the length of OA is the same as that of OC which is=2n+5
Similarly the length of DO is the same as that of OB which is=4n-3
Now from Pathagoras theorem we get
(AD)=SQRT((DO)^2+(OA)^2)
(AD)=SQRT((4N-3)^2+(2N+5)^2)
(AD)=SQRT((16n^2+9-24n)+(4n^2+25+20n))
(AD)=SQRT(20n^2+34-4n)
Answer:
This is impossible to answer, unless there is a picture that is not there.
Step-by-step explanation:
8 x 8 = 64
10 x 6 + 4 = 64
32 x 2 = 64
12 x 5 + 4 = 64
13 x 4 + 12 = 64