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2 years ago

Write an equation of the line that passes through (0,4) and (1,2

Mathematics

1 answer:

Aleks04 [339]2 years ago

7 0

Answer:

y = mx + b

y = -2x + 4

Step-by-step explanation:

m = 2 - 4 / 1 - 0 = -2 / 1 = -2

m (slope) = -2

y = mx + b (0,4)

4 = -2x + 0

-0 - 0

4 = -2x

-2 -2

-2 = x

Equation: y = mx + b

y = -2x + 4

Hope that helps!! Please give me brainliest!!

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Find the coordinates of the third vertex that completes the construction of a right triangle on the coordinate plane.

Neko [114]

Answer:

(7,a) Where a ∈ R - {7}

OR

(-2,a) where a ∈ R - {-2}

Step-by-step explanation:

The coordinates of the given line from the right to the left are:

(7,1) and (-2,1)

So, to make a right triangle, we need to make a right angle or by another words, we need to a make a perpendicular line to the given line (i.e: a vertical line parallel to the y-axis at one of the given points)

So, the third vertex must be on the line x=7 or x=-2

So, the coordinates of the third vertex is:

(7,a) Where a ∈ R - {7}

OR

(-2,a) where a ∈ R - {-2}

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3 years ago

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Answer:
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Explanation:
I’m guessing you meant to write
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Amiraneli [1.4K]

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2 years ago

Solve Highschool Pre cal

Bezzdna [24]

Option C:

$\ln 64 y^{2}$

Solution:

Given expression: 2 ln 8 + 2 ln y

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Applying log rule $\log a+\log b=\log (a b)$ in the above expression.

⇒ $\ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)$

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2 years ago

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Lelu [443]

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$\left(6\cos-\dfrac{\pi}{5},6\sin-\dfrac{\pi}{5}\right)$

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3 years ago