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Black_prince [1.1K]

3 years ago

14

Can you help me with this

1 answer:

IgorC [24]3 years ago

3 0

The correct answer is

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Choose the product. -7 p3 (4 p2 + 3 p - 1)

sashaice [31]

Answer:

The product is -28p5-3p4+7p4

Step-by-step explanation:

In this case we will use -7p3 to multiply all the figures in the bracket

Which means -28p5-3p4+7p3

Always remember that -×-=+ , +×+=+ ,-×+=-...

Thanks

7 0

3 years ago

Amy earns £10.00 per hour. She gets a raise, and her new hourly rate is £11.50. What is the percentage change in her hourly rate

Nookie1986 [14]

Answer: 15%

Step-by-step explanation:

% change = change/ actual value x 100

Change = 11 .50 - 10 = 1.5

Therefore % change = 1.5/10 x 100

= 15%

7 0

4 years ago

Read 2 more answers

How long a line can you make using all the 3/8 inch strips

Paraphin [41]

The total amount of lenght that the line will have depends on the amount of strips, and the result is equal to the multiplication of the amount of strips, x, and the length of the strips 3/8 inch

total_length = (3/8)x

where x is the amount of strips, and the total length is in inches

6 0

3 years ago

A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

aleksklad [387]

The spider's movement is an illustration of a parabola.

The equation of a parabola is: $\mathbf{y = -\frac{1}{160}(x - 40) + 10}$
The focus of a parabola is: (40,-30)
The axis of symmetry is: $\mathbf{x = 40}$
The directrix is: $\mathbf{y = 50}$

<u>(a) The equation</u>

The spider passes through the origin.

So, we have:

$\mathbf{(x,y) = (0,0)}$

The spider jumps to a maximum height of 10mm, midway 80mm.

So, the vertex is:

$\mathbf{(h,k) = (40,10)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

So, we have:

$\mathbf{0 = a(0 - 40)^2 + 10}$

Subtract 10 from both sides

$\mathbf{a(0 - 40)^2 =- 10}$

$\mathbf{1600a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{160}}$

Substitute $\mathbf{a =- \frac{1}{160}}$ and $\mathbf{(h,k) = (40,10)}$ in $\mathbf{(h,k) = (40,10)}$

$\mathbf{y = -\frac{1}{160}(x - 40) + 10}$

<u>(b) The focus, directrix and the axis of symmetry</u>

The focus of a parabola is:

$\mathbf{Focus= (h, k + p)}$

Where:

$\mathbf{p = \frac{1}{4a}}$

So, we have:

$\mathbf{p = \frac{1}{4 \times -1/160}}$

$\mathbf{p = -\frac{160}{4}}$

$\mathbf{p = -40}$

So, we have:

$\mathbf{Focus = (40,10-40)}$

$\mathbf{Focus = (40,-30)}$

The axis of symmetry is:

$\mathbf{x = h}$

So, we have:

$\mathbf{x = 40}$

The directrix is:

$\mathbf{y = k - p}$

$\mathbf{y = 10 + 40}$

$\mathbf{y = 50}$

Read more about parabolas at:

brainly.com/question/25237745

4 0

3 years ago

Find the inverse function<br> f(x)=3\sqrt{x}+7

Likurg_2 [28]

let y = 3/sqrt(x) + 7

y -7 = 3\sqrt(x)

(y-7)^3 = x

f^-1(x) = (y-7)^3

6 0

4 years ago