So first find the moles of the H₂SO₄: Mass = Moles x RFM
so mass = 5.25 x 98 = 514.5g of <span>H₂SO₄</span>
so to find how many Liters of solution use:
Volume = Density x Grams of solute (per kg +1000)
density = 1.266 x 514.5 +1000 = 1917.357kg/l
now use equation: Conc. = Moles / Volume of solution to find the conc.
Conc. = 5.25 x 1917.357 = 4.39Mol⁻¹
Hope that helps
Answer:
C 16
Explanation:
Since there are 6 valence electrons, this belongs in the same column as Oxygen. In fact, this is a diagram of a neutral oxygen atom with 8 total electrons.
Answer: True.
Explanation.
The group 7A is actually named group 17.
That group is the halogens: F, Cl, Br, I, At, and Ts (Ts is one of the last elements discovered).
Those elements have 7 valence electrons (notice that it is the same number as the second digit in 17).
The atoms with 7 valence electrons will "easily" gain one electron to get the configuration of the next noble gas (8 valence electrons). That is why these elements gain electrons to form ions.
When atoms gain electrons form anions (negative ions). For example: F(-), Cl(-), Br(-), I(-).
Answer:
(b) manganese-51
Explanation:
Positron emission or β+ decay is emission of positron from nucleus. It is observed for the nuclides in which ratio to the neutron and the proton is low. These type of nuclides lie below band of the stability. Positron decay is conversion of proton into neutron with emission of positron.
Manganese-51 is most likely to decay by the positron emission.
The n:p ratio:
For Cr-53 is:
For Mn-51 is:
For Fe-59 is:
As stated above, positron decay occurs when n:p ratio is low.
<u>Thus, Mn-51 has the lowest n:p ratio and therefore is likely to decay by the positron emission.</u>
