Answer:
i would say the 3rd answer
The correct answer for this question is this one:
<span>Starting with ln[(2X - 1)/(X - 1)] = t, solve for X in terms of t:
(2X - 1)/(X - 1) = e^t ---->
2X - 1 = (X - 1)*e^t ---->
2X - X*e^t = 1 - e^t ----->
X*(2 - e^t) = 1 - e^t ----->
X = (1 - e^t)/(2 - e^t) = (e^t - 1)/(e^t - 2).
Now differentiate ln[(2X - 1)/(X - 1)] = ln(2X - 1) - ln(X - 1) = t implicitly:
(2/(2X - 1))*dX/dt - (1/(X - 1))*dX/dt = 1
dX/dt*((2*(X - 1) - (2X - 1)) / ((2X - 1)(X - 1))) = 1
dX/dt*(-1) = (2X - 1)(X - 1)
dX/dt = (X - 1)(1 - 2X).</span><span>
Hope this helps you answer your question.</span>
No thanks do u k how tired i am to look for more info its sooo boring like u could have written it no big deal
Answer:
First look at the number of bricks alone.
Going from 50 bricks to 60 bricks is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 60/50
Next look at the time alone.
Going from 30 minutes to 20 minutes is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 30/20
Now you can just multiply everything.
= 5*60/50*30/20
= 5*6/5*3/2
= 90\10
= 9.