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olasank [31]
3 years ago
5

HELP PLEASE?!? I tried to multiply the numbers that they were giving me but I got something really different then the calculator

. HELP REALLY APPRECIATED

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0
12.4×3.80=47.12
4×1.99=7.96
2×1.55=3.10

All will give , 58.18

so you should write in answer,
I am not agree because the total cost is different from the total given cost !!
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2÷ 1/2 = 2/1 × 2/1 = 4

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answer is V = 64 inches cubed.
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Read 2 more answers
Gavin likes biking. This week his goal is to bike about 65 total miles over four days. Each day he wants to ride 1.5 times as fa
IRISSAK [1]

Step-by-step explanation:

let the first-day ride be x

Then the second-day ride will be =1.5 x

The third-day ride will be=1.5(1.5x)      

The Fourth-day ride will be=1.5*1.5(1.5x)  

hence for the four days the distance covered is

65=x+1.5x+1.5*1.5x+1.5*1.5*1.5x

65=x+1.5x+2.25x+3.375x

65=8.125x

divide both sides by 8.125 we have

x=65/8.125

x=8mile

the first-day ride be x=8miles

the second-day ride will be =1.5 x =1.5*8= 12miles

The third-day ride will be=1.5(1.5x) = 18miles

The Fourth-day ride will be=1.5*1.5(1.5x) = 27miles

5 0
3 years ago
A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me
Neporo4naja [7]

Answer:

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

Q = \Delta U

Q = m \cdot c \cdot \Delta T

The specific heat is clear in the previous expression and finally computed:

c = \frac{Q}{m\cdot \Delta T}

c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

6 0
3 years ago
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