Answer:
0.3891 = 38.91% probability that only one is a second
Step-by-step explanation:
For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
17% of its goblets have cosmetic flaws and must be classified as "seconds."
This means that 
Among seven randomly selected goblets, how likely is it that only one is a second
This is P(X = 1) when n = 7. So


0.3891 = 38.91% probability that only one is a second
W - a width
3w - a length
27 ft² - an area
Therefore:
w · 3w = 27
3w² = 27 |:3
w² = 9 → w = √9 → w = 3
3w = 3 · 3 = 9
width = 3
length = 9
The perimeter:
P = 2 · width + 2 · length
P = 2 · 3 + 2 · 9 = 6 + 18 = 24 ft.
Answer:
2
Step-by-step explanation:
We can set up equation for this one.
Let's say the number is X.
the sum of X and 14 can be expressed as : X+14
five times the sum of X and 14 can be expressed as 5(x+14)
and 5(X+14) = 80

The number is 2