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Volgvan
3 years ago
15

Solve the inequality. 3x + 7 > 4x + 2

Mathematics
2 answers:
ankoles [38]3 years ago
7 0
5>x because you can subtract 5 from both sides and 3x from both sides

Nutka1998 [239]3 years ago
5 0
By solving this kind inequality, we would then have to find what does (x) equal, and then from here, we would determine which would be greater.

rearrange: \\      3*x+7-(4*x+2)\ \textgreater \ 0 \\ \\  Multiply \ both \ sides \ by \ (-1) \\ \\

Then after, we add both sides by 5.

 3x + 7= 3*5+7=22

4x + 2=4*5+2=22

<span>3x + 7 (x) 4x + 2</span>
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the distance between two towns on a map is 6cm. the actual distance between 2 towns is 48km what is the scale on the map​
kodGreya [7K]

Answer:

1 cm=8 km

Step-by-step explanation:

We can use a ratio to determine the scale.  Take the distance on the map  on the left and the "real distance" on the right

6 cm=48 km

Divide by 6

6 cm/ 6 = 48 km /6

1 cm=8 km

4 0
2 years ago
Mnv<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%20%5Cfrac%7B7%7D%7B%3F%7D%20%20%3D%204" id="TexFormula1" title="2 \times \
faltersainse [42]

Answer:

? = 7/2

Step-by-step explanation:

? = x

a denominator can’t be equal to 0

x ≠ 0

14/x = 4

14 = 4x

x = 7/2

6 0
2 years ago
Solve using the standard algorithm <br> 1.03 +0.08
nataly862011 [7]

Answer:

1.11

Step-by-step explanation:

1.03+0.08=1.11

4 0
3 years ago
I don't understand this question. Could someone help me? The graph is what is being looked at. I've already tested if they are o
Alex Ar [27]

The answer should be obtuse. I'm not sure why it is saying it's incorrect but none of the other answers make sense.

5 0
2 years ago
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
2 years ago
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