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arlik [135]
3 years ago
13

Is the following graph a function

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

Yes, because for each value of x there is only one y.

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People use water to​ cook, clean, and drink every day. An estimate of 33.9​% of the water used each day is for cooking. If a fam
Lady_Fox [76]

Answer:

23 gallons of water

Step-by-step explanation:

People use water to​ cook, clean, and drink every day. An estimate of 33.9​% of the water used each day is for cooking. If a family uses 67.8 gallons of water a day for cooking​, how many gallons do they use every​ day?

This is calculated as:

33.9 % × 67.8 gallons of water

= 0.339 × 67.8 gallons of water

= 22.9842 gallons of water

Approximately = 23 gallons of water

Therefore, 23 gallons of water are used everyday for cooking

5 0
2 years ago
A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
Simplify 8 2(10 – r).
MissTica
Is the 8 with the problem?
8 0
3 years ago
[-22(-0.2)] - [ (2) x 0.22] =<br><br> This stuff is hard...!!!
Ede4ka [16]

-22(-0.2) - [ 2 (0.22)]

4.4 - 0.44 = 3.96

8 0
3 years ago
Read 2 more answers
Solve the equation 14z=224
kolbaska11 [484]

Answer:

16

Step-by-step explanation:

224/14=16

6 0
3 years ago
Read 2 more answers
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