In 3 years she will earn 1,800.
15,000 x .12=1,800
Answer:
-5/2, -2, 1.7
Step-by-step explanation:
Answer: 8 minimum work stations is what would be needed.
Step-by-step explanation:
The cycle time is computed as the operating time daily divided by the scheduled output.
It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.
Therefore,
If you need to produce 30units/hour.
The average cycle time is as follow:
The average cycle time is the average time between the completions of units.
60/30= 2 average cycle time
=16/2
=8
8 work stations is the minimum number that would be needed.
It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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The first one is 10ab + 20
