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joja [24]
2 years ago
12

I need help with this one too please !i mark brainliest to everyone

Mathematics
2 answers:
denis-greek [22]2 years ago
5 0

Answer:

I believe A is the answer

iren [92.7K]2 years ago
3 0
Anser is B) because it crosses the negative sevin on the negative side
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Suppose that diameters of a new species of apple have a bell-shaped distribution with a mean of 7.25cm and a standard deviation
Ulleksa [173]

Answer:

95%

Step-by-step explanation:

5 0
3 years ago
In a school, two-fifths of the pupils are girls. how many pupils are there if 96 are boys
NikAS [45]
38.4 is the answer i think because u divide 96 by 5 then times it by 2 to get two fifths 
5 0
3 years ago
In triangles ABC and LMN, ∠A ≅ ∠L, ∠B ≅ ∠M, and ∠C ≅ ∠N. Is this information sufficient to prove triangles ABC and LMN congruent
ipn [44]

Answer:

No

Step-by-step explanation:

No. We have 3 angles of triangle ABC congruent to 3 corresponding angles of triangle LMN. That is AAA. To use ASA, you need two angles and an included side. With three angles, you can prove the triangles similar, but not congruent.

5 0
2 years ago
Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
-Dominant- [34]
1) -3(5x+2y=-3)⇒ -15x-6y=9
                                             ⇒ -9x=27
     2(3x+3y=9)⇒ 6x+6y=18

2) -9x/-9=27/-9 ⇒ x=-3 

3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6

Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

6 0
3 years ago
The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre
boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = \frac{x-mean}{standard deviation}

= \frac{174-177}{26}

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

8 0
3 years ago
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