The answer is true I have had this question before
Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
Answer:
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Step-by-step e.xplanati:kljkjk
Here's are the steps to solving it.
3-a+5-2a=17
-3a=9
a=-3
Answer:
a.0 ≤ x ≤ 30, where x is a whole number
Step-by-step explanation:
a vacation rental company uses the function v(x)=250x+75
x is the number of nights
maximum number of nights = 30
The number of nights cannot be negative
The domain is the set of x values for which the function is defined
we ignore the negative value for x in the domain because number of nights cannot be negative
so x starts at 0 and maximum is 30
number of nights should be a whole number
0 ≤ x ≤ 30, where x is a whole number
