Ask question

Ask question

All categories

3 years ago

11

The total cost after tax to repair Deborah’s computer is represented by 0.09(60h)+60h, where h represents the number of hours it

takes to repair Deborah’s computer. What part of the expression represents the amount of tax Deborah has to pay? Explain.
If and only if all work is shown and understandable then you will be marked brainliest. DO NOT answer if you don't know the answer that is stealing points and it will be reported, if you have a guess use the comment section.

1 answer:

tia_tia [17]3 years ago

4 0

Answer:

0.09 OR 9% is her tax

Step-by-step explanation:

Deborah has to pay 9% for tax. So is someone worked on her computer for two hours then she pays 9% on $120 worth of work. So her tax amount would be $10.800 and her total amount would be 10.8 +120 = $130.80.

You might be interested in

Lisa and Daisy work at a hair salon. The salon charges $18 for a hair styling session with Lisa and $12 for a session with Daisy

Kitty [74]

Our equation is:
18x + 12y = 216

if Daisy calls in sick that day that means that that day she attained y=0 customers. now we need to solve for x.

18x = 216
x = 12

Answer is 12.

3 0

3 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Only tick questions please help me

goldfiish [28.3K]

6/76 x 3
Jsjsjjsjsjsjjsja

8 0

3 years ago

Prove that the value of the expression does not depend on a:<br><br> a−(6a−(5a−8))

djyliett [7]

Step-by-step explanation:

a−(6a−(5a−8))

a-(6a-5a+8)

a-6a+5a-8

6a-6a-8

0-8

=-8

so the answer doesn't depend on a

3 0

3 years ago

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, a

Bogdan [553]

Answer:

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 $feet^2$

Step-by-step explanation:

Given: Lawn is rectangular in shape

Length of lawn is 5 feet more than twice its breath/width

Perimeter of Lawn = 250 feet

To find: (a) Length and width of lawn

(b) Area of Lawn

First let the a variable for width/breadth. Say, Width = b.

So, the length of lawn = 2b + 5

Perimeter of Rectangle = 2 × ( length + width )

Now, substitue given values in this formula

∴ Perimeter of Lawn = 2 × ( 2b + 5 + b )

$250 = 2\times{(2b+b+5)}\\250= 2\times{(3b+5)}\\3b+5 = \frac{250}{2}\\3b = 125 -5\\3b = 120\\b=\frac{120}{3}\\b=40$

∴width = 40 feet

⇒ length = 85 feet

Now we find are of lawn using formula of area of rectangle

Area of lawn = length × width

= 85 × 40

= 3400 $feet^2$

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 $feet^2$

7 0

3 years ago