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WARRIOR [948]
3 years ago
5

Need help please with this question

Mathematics
1 answer:
inessss [21]3 years ago
8 0
There are 5 squares of dimensions 3 x 3.
5 x (9) = 45 sq. in.

There are 4 right triangles of leg lengths of 6.
4 x (18) = 72 sq. in.

45 + 72 = 117 sq. in.
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Sixteen is no more than twice a number minus four.
Taya2010 [7]

16 ≤ 2x - 4 is the answer

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2 years ago
Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a
earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

<em><u>Solution:</u></em>

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

<em><u>Alex is 12 years older than George</u></em>

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

<em><u>Carl is Three times older than Alex</u></em>

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

<em><u>The sum of their ages is 68</u></em>

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

<em><u>Substitute eqn 1 and eqn 2 in eqn 3</u></em>

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

<em><u>Substitute a = 16 in eqn 2</u></em>

c = 3(16) = 48

c = 48

<em><u>Substitute a = 16 in eqn 1</u></em>

g = 16 - 12 = 4

g = 4

<em><u>Find the ratio of George’s age to Carl’s age to Alex’s age</u></em>

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

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