Question

Solve for x in the equation 2 x squared minus 5 x + 1 = 3.

Answer 1

Answer:

$x=\frac{5(+/-)\sqrt{41}} {4}$

Step-by-step explanation:

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2} -5x+1=3$  

equate to zero

$2x^{2} -5x+1-3=0$  

$2x^{2} -5x-2=0$  

so

$a=2\\b=-5\\c=-2$

substitute in the formula

$x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(2)(-2)}} {2(2)}$

$x=\frac{5(+/-)\sqrt{41}} {4}$