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NeX [460]
4 years ago
12

He unit circle has a radius of 1 unit and is centered at the origin. It is dilated so that it passes through the point (4, 0).

Mathematics
1 answer:
Advocard [28]4 years ago
5 0
We know that

if the dilated circle <span>passes through the point (4, 0)
so
the new radius is the distance from the origin to point (4,0)
d=</span>√[(4-0)²+0²]-----> d=√16------> d=4 units

the new radius  is 4 units
original radius is 1 units

[new radius]=[scale]*[original radius]
scale=new radius/original radius-----> scale=4/1-----> 4

the answer is
<span>the scale factor of dilation is 4</span>
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What is the equation of the line that passes through (-2, 2) and (1, -4)?
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Answer:

y = - 2x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁  = (- 2, 2) and (x₂, y₂ ) = (1, - 4)

m = \frac{-4-2}{1+2} = \frac{-6}{3} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 2), then

2 = 4 + c ⇒ c = 2 - 4 = - 2

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3 years ago
What is the discriminat of 2x+5x^=1
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Answer:

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5 0
3 years ago
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TEA [102]

Answer:

All real numbers

Step-by-step explanation:

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Please help me with this question
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Answer:

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3 0
3 years ago
3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3
ozzi

Answer:

<h2>3. Infinitely many</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\(1)\\\text{if}\ a=d,\ b=e,\ c=f,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=5\end{array}\right\\(2)\\\text{if}\ a=d,\ b=e,\ c\neq f,\ \text{then the system of equations has no solution}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=-5\end{array}\right

(3)\\\text{if}\ a\neq d\ \text{or}\ b\neq e,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}x-3y=5\\2x-3y=5\end{array}\right

\text{We have:}\\\\\left\{\begin{array}{ccc}2x=-10y+6&\text{add 10y to both sides}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}2x+10y=6&\text{divide both sides by 2}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}x+5y=3\\x+5y=3\end{array}\right

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4 years ago
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