Ask question

Ask question

All categories

4 years ago

12

He unit circle has a radius of 1 unit and is centered at the origin. It is dilated so that it passes through the point (4, 0).

1 answer:

Advocard [28]4 years ago

5 0

We know that

if the dilated circle <span>passes through the point (4, 0)
so
the new radius is the distance from the origin to point (4,0)
d=</span>√[(4-0)²+0²]-----> d=√16------> d=4 units

the new radius is 4 units
original radius is 1 units

[new radius]=[scale]*[original radius]
scale=new radius/original radius-----> scale=4/1-----> 4

the answer is
<span>the scale factor of dilation is 4</span>

You might be interested in

X² + 6x +8=0<br> In factoring algorithm

Mama L [17]

Answer:

(x+2)(x+4)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

53% of what number is 93?

Liono4ka [1.6K]

Answer:

About 175.47

Step-by-step explanation:

*The answer is decimal*

.53*x=93

93/.53= about 175.47

6 0

3 years ago

Read 2 more answers

Alx+b) = 4x + 10

Leokris [45]

Answer:

a=4, b=5/2

Step-by-step explanation:

Assuming the given equation is

$a(x + b) = 4x + 10$

We expand the left hand side to get:

$ax + ab = 4x + 10$

If this equation must have infinitely many solutions, then

$ax = 4x \\ \implies \: a = 4$

Also we must have

$ab = 10$

Put a=4 to get:

$4b = 10$

$b = \frac{10}{4} = \frac{5}{2}$

3 0

4 years ago

Which expression is equivalent to 24 Superscript one-third

Tems11 [23]

Answer:

The expression that is equivalent is 2 RootIndex 3 StartRoot 3 EndRoot :

$2\sqrt[3]{3}$

Step-by-step explanation:

Hi

As we have 24 Superscript one-third, this is $(24)^{\frac{1}{3}} =\sqrt[3]{24}$ .

$\sqrt[3]{24}=\sqrt[3]{8*3}=\sqrt[3]{8} \sqrt[3]{3}$ , therefore

$\sqrt[3]{8} =2$ , so $\sqrt[3]{8} \sqrt[3]{3}=2\sqrt[3]{3}$ .

3 0

4 years ago

BRAINLIEST IS AWNSERED

Phantasy [73]

Answer:

Y= -1x -3

Step-by-step explanation:

0,3

1,2

2-3=-1

1-0=1

-1/1=-1

y intercept is 3

6 0

3 years ago