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olchik [2.2K]
3 years ago
11

HELP WITH ALL Determine the composite functions of the following set of functions

Mathematics
1 answer:
elixir [45]3 years ago
7 0

QUESTION 1

i) Given f(x)=5x-2 and g(x)=x^2.

(f\circ g)=f(g(x))

(f\circ g)=f(x^2)

We plug in x^2 into f(x)=5x-2

(f\circ g)=5x^2-2

ii) Given f(x)=5x-2 and g(x)=x^2.

(g\circ f)=g(f(x))

(g\circ f)=g(5x-2)

We plug in 5x-2 into g(x)=x^2

(g\circ f)=(5x-2)^2

(g\circ f)=25x^2-10x-10x+4

(g\circ f)=25x^2-20x+4

QUESTION 2

i) Given g(x)=x^2-4 and h(x)=\sqrt{2x+1}.

(h\circ g)=h(g(x))

(h\circ g)=h(x^2-4)

We plug in x^2-4 into h(x)=\sqrt{2x+1}

(h\circ g)=\sqrt{2(x^2-4)+1}

(h\circ g)=\sqrt{2x^2-8+1}

(h\circ g)=\sqrt{2x^2-7}

ii) Given g(x)=x^2-4 and h(x)=\sqrt{2x+1}.

(g\circ h)=g(h(x))

(g\circ h)=g(\sqrt{2x+1})

We plug in \sqrt{2x+1 into g(x)=x^2-4

(g\circ h)=(\sqrt{2x+1})^2-4

(g\circ h)=2x+1-4

(g\circ h)=2x-3

QUESTION 3

i) Given g(x)=x+5 and h(x)=\sqrt{x-4}.

(g\circ h)=g(h(x))

(g\circ h)=g(\sqrt{x-4})

We plug in \sqrt{x-4} into g(x)=x+5

(g\circ h)=\sqrt{(x-4)+5}

ii) Given g(x)=x+5 and h(x)=\sqrt{x-4}.

(g\circ g)=g(g(x))

(g\circ g)=g(x+5)

We plug in x+5 into g(x)=x+5

(g\circ g)=(x+5)+5}

(g\circ g)=x+10}

QUESTION 4

The given functions are;

f(x)=-2x+1 and g(x)=-x^2  

f\circ f=f(f(x))

f\circ f=f(-2x+1)

f\circ f=-2(-2x+1)+1)

f\circ f=4x-2+1)

f\circ f=4x-1)

ii)  

g\circ g=g(g(x))

g\circ g=g(-x^2)

g\circ g=-(x^2)^2

g\circ g=-x^4

QUESTION 5

f(x)=5x-2;g(x)=x^2;h(x)=-3x

h\circ g\circ f=h\circ (g(f(x))

h\circ g\circ f=h\circ (g(5x-2))

h\circ g\circ f=h\circ ((5x-2)^2)

h\circ g\circ f=h\circ (25x^2-20x+4)

h\circ g\circ f=h(25x^2-20x+4)

h\circ g\circ f=-3(25x^2-20x+4)

h\circ g\circ f=-75x^2+60x-12)

ii.

f\circ f\circ g=f\circ (f(g(x))

f\circ f\circ g=f\circ (f(x^2)

f\circ f\circ g=f\circ (5x^2-2)

f\circ f\circ g=f(5x^2-2)

f\circ f\circ g=5(5x^2-2)-2

f\circ f\circ g=25x^2-10-2

f\circ f\circ g=25x^2-12

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