You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:
5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625
so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625
x = log₅ 5⁻⁴
log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:
x = -4 is your answer
if the exponent dropping down doesn't make sense to you, you can think of it in another way:
x = log₅ 5⁻⁴
expand the expression so that the exponent moves in front of the log function:
x = (-4) log₅ 5
then, still, log base 5 of 5 simplifies to 1, so you're left with:
x = (-4)1 or x = -4
Answer:
If you meant [80 + (8*4) ]/2, then [80 + (8*4) ]/2=56
or if you meant 80 + [ 8*4 / 2], then 80 + [ 8*4 / 2] = 96
Step-by-step explanation:
Evalute the expression. 80 + (8x4) divided by 2
so do you mean
the whole expression 80 + (8x4) is over 2 ?
If so then:
evaluate 8x4 = 8 * 4 = 32.
so we have 80 + (8x4) is over 2 = (80 + 32)/2 = 112/2 = 56
If you meant 80 + [ 8*4 / 2]
then 80 + [ 8*4 / 2] = 80 + 8*2 = 80 + 16 = 96
Answer:
Step-by-step explanation:
24 + 3r >= 100 is the equation
Answer:
12
Step-by-step explanation:
you subtract the ordered pairs on the sides. then the ones on the top and bottom. then you add all of the sides
