Solve the logarithmic equation: x= log5 (1/625)=
1 answer:
You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number: 5^-1 = 1/5 . . . keep trying those. . . 5^-4 = 1/625 so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625 x = log₅ 5⁻⁴ log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down: x = -4 is your answer if the exponent dropping down doesn't make sense to you, you can think of it in another way: x = log₅ 5⁻⁴ expand the expression so that the exponent moves in front of the log function: x = (-4) log₅ 5 then, still, log base 5 of 5 simplifies to 1, so you're left with: x = (-4)1 or x = -4
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Improper 7/4 and mixed number 1 3/4
First Equation:
0.6 +(0.4+0.9) =n
Step 1: do parentheses first:
0.4+0.9 = 1.3
Step 2 : Add 0.6 + 1.3
0.6 + 1.3 = 1.9
n= 1.9
Second Equation:
(1.57 + 0.75) + 0.25 + n
Step 1: do parentheses first:
1.57 + 0.75 = 2.50
Step 2: Add 2.50 + 0.25 = 2.75
Step 3: Add 2.75 and n = 2.75+n
Final Answer:
1.9 +2.75+n = 4.65 +n
Hope this helps!!
Answer: y^2-4y-6
Step-by-step explanation:
Answer:
Hey there!
16(4x^6+y^2)(2x^3+y)(−2x^3+y)
Let me know if this helps :)
Answer:
32 is your answer
cancel out -2 by adding two to negative two, but what you do on one side you have to do to the other so then add 2 to thirty and your left with x =32