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3 years ago

Pls help me but pls dont send me a link im begging u

Mathematics

2 answers:

dimaraw [331]3 years ago

8 0

Answer:

I dont know the 1st one but the bottom one is

Yes

Vesna [10]3 years ago

3 0

Answer:

Step-by-step explanation:

24 + 3r >= 100 is the equation

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Can someone help answer this

kolezko [41]

Answer:

v = 55

Step-by-step explanation:

Plug in the values provided into the equation

v = u + at

v = 23 + 8 * 4

Solve

v = 23 + 8 * 4

v = 23 + 32

6 0

3 years ago

Read 2 more answers

3. Write an equation in point-slope form for the line through the given point with the given slope.

jok3333 [9.3K]

Answer:

Step-by-step explanation:

recall that point-slope form of a linear equation is expressed as follows

y - y1 = m (x - x1)

where m = slope and (x1, y1) is the coordinate of any point on the line

so, here we have m = (3/5), x1 = 4 and y1 = -6

substitute these into the formula

y - (-6) = (3/5) (x - 4)

y + 6 = (3/5) (x - 4)----> answer

5 0

4 years ago

Read 2 more answers

What is the equation of the line that passes through the point (4,7) and has a slope of o?

Svetlanka [38]

Answer:

The equation of the line that passes through the point (4,7) and has a slope of 0 will be:

$y=7$

Step-by-step explanation:

As we know the equation of a line in a slope-intercept form of an equation is

$y = mx + b$

Here,

m is the slop

b is the y-intercept

substituting the point (4,7) and slope m=0

$y = mx + b$

$7=0(4)+b$

$7=0+b$

$b=7$

Therefore, the equation of the line that passes through the point (4,7) and has a slope of 0 will be:

$y = mx + b$

$y=0x+7$

$y=7$

5 0

3 years ago

What two rational expressions sum to 3x+4/x^2-6x+5?

Lubov Fominskaja [6]

Answer:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

Step-by-step explanation:

The given rational expression is:

$\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}$

We can use concept of Partial Fractions to solve this problem. Let,

$\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}$

Multiplying both sides by (x - 1)(x - 5), we get:

$3x+4=A(x-5)+B(x-1)$

Substituting x = 5, we get:

$3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}$

Substituting x = 1, we get:

$3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}$

Substituting the value of A and B, back in the original equation, we get:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

4 0

3 years ago

Solve the quadratic equation by factoring-

shtirl [24]

Answer:

c- (2x+3)(x+1)

Step-by-step explanation:

Let me know if you want step by step

3 0

3 years ago