The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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The answer is 1 1/2 because if you divide 4 into 6 you get I need and a half or 1.5
Answer: The next three terms =2.56, - 1.024 and 0.4096
Step-by-step explanation:
Common Ratio of a Geometric sequence, R is calculated as
=a2/a1 = -40/100=-0.4
or a3/a2=16/ -40 = -0.4
such that the next three terms are
5th term = -6.4 x -0.4=2.56
6th term= 2.56 x -0.4 =-1.024
7TH term= -1.024 x -0.4=0.4096
Answer:the answer is B
Step-by-step explanation:Bisect each of the angles with vertices at their houses
