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3 years ago

8

A Town had about 2120 acres of Pinetree’s 40 years ago only about 13 of the Pinetree‘s remain how many acres of Pinetree’s remai

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1 answer:

grin007 [14]3 years ago

8 0

275.6 acres of pine trees remain.

2,120 x 0.13 = 275.6

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amm1812

I have no clue ...I'm nt so good in maths

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3 years ago

Whats 1/18 as a decimal can someone please help me

sergij07 [2.7K]

1/18 as a decimal is 0.055555555555556 because you divide one by eighteen and get that number.

Hope this helped!

6 0

3 years ago

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

guajiro [1.7K]

The volume of the metal box if the box was completely solid (V1), is:

V1=(12 inches)³
V1=1728 inches³

As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:

W=12 inches-(3 inchesx2)
W=6 inches

Then, the volumen of the no solid metal box is:

V2=(6 inches)³
V2= 216 inches³

Therefore, the volume of metal needed to smelt the cubical metal box, is:

V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³

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3 years ago

What is the perimeter of a triangle with sides of lengths 5, 8, & x?

Anastaziya [24]

The perimeter of a triangle can be found by adding up all the sides

so the perimeter is :
5 + 8 + x =
13 + x <==

4 0

3 years ago

Rationalize the denominator and simplify.

cestrela7 [59]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3151018

——————————

$\mathsf{\dfrac{3\sqrt{6}+5\sqrt{2}}{4\sqrt{6}-3\sqrt{2}}}$

Multiply and divide by the conjugate of the denominator, which is $\mathsf{4\sqrt{6}+3\sqrt{2}:}$

$\mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}}$

Expand those products and eliminate the brackets:

$\mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(3\sqrt{6}+5\sqrt{2}\big)\cdot 3\sqrt{2}}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(4\sqrt{6}-3\sqrt{2}\big)\cdot 3\sqrt{2}}}\\\\\\ \mathsf{=\dfrac{12\cdot \big(\sqrt{6}\big)^2+20\sqrt{2}\cdot \sqrt{6}+9\cdot \sqrt{6}\cdot \sqrt{2}+15\cdot \big(\sqrt{2}\big)^2}{16\cdot \big(\sqrt{6}\big)^2-12\cdot \sqrt{2}\cdot \sqrt{6}+ 12\cdot \sqrt{6}\cdot \sqrt{2}-9\cdot \big(\sqrt{2}\big)^2}}\\\\\\ \mathsf{=\dfrac{12\cdot 6+20\sqrt{2\cdot 6}+9\sqrt{6\cdot 2}+15\cdot 2}{16\cdot 6-12\sqrt{2\cdot 6}+ 12\sqrt{6\cdot 2}-9\cdot 2}}\\\\\\ \mathsf{=\dfrac{72+20\sqrt{12}+9\sqrt{12}+30}{96-12\sqrt{12}+12\sqrt{12}-18}}$

$\mathsf{=\dfrac{72+29\sqrt{12}+30}{96-18}}\\\\\\ \mathsf{=\dfrac{102+29\sqrt{2^2\cdot 3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot \sqrt{2^2}\cdot \sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot 2\sqrt{3}}{78}}$

$\mathsf{=\dfrac{102+58\sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{\,\diagup\!\!\!\! 2\cdot \big(51+29\sqrt{3}\big)}{\diagup\!\!\!\! 2\cdot 39}}$

$\mathsf{=\dfrac{51+29\sqrt{3}}{39}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

4 0

3 years ago