Answer:
B. r + l = 45; 2r + 3l = 96
39 regular; 6 long-distance
Step-by-step explanation:
There were 45 baskets, so
(1) r + l = 45
There were 96 points in the game, so
(2) 2r + 3l = 96
Solve equation (1) for l
l = 45 – r Substitute the value for l in Equation (2)
2r + 3(45 – r) = 96 Remove parentheses
2r + 135 - 3r = 96 Combine like terms
-r + 135 = 96 Subtract 135 from each side
-r = -39 Multiply each side by -1
r = 39 Substitute the value of r in Equation (1)
39 + l = 45 Subtract 39 from each side
l = 6
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Check:
(1) 39 + 6 = 45
45 = 45
(2) 2×39 + 3×6 = 96
78 + 18 = 96
96 = 96
Seven units long. The distance between 2 sides, in this example is 6, and -1. The distance between 6 and -1 is 7, so when you add units, you get 7 units.
<h3>Answer: D) center E, scale factor 1/4</h3>
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Explanation:
Point E is the center of the dilation (we can think of this as the origin point). This is because point E is in the same exact location as point E'. This is a fixed point. The other points move.
To find the scale factor, divide E'F' over EF
scale factor = (E'F')/(EF)
scale factor = 2/8
scale factor = 1/4
Keep in mind that EF = EF'+F'F = 2+6 = 8.
Answer:
This will explain it
Step-by-step explanation:
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
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The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
