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morpeh [17]
2 years ago
11

How can you determine the coordinates of the care after a reflection over either axis

Mathematics
1 answer:
MrRa [10]2 years ago
5 0
Well when you reflect over a coordinate it puts the same information on the opposite side, for example:
3,5 reflected now its -3,5
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I need help with this please.
SSSSS [86.1K]

Answer:

f )  x+72=90(complementary angle)

x= 90-72

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g )x+77=90

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7 0
3 years ago
What is the quadratic factorization of <br>x^2+5x+6=?​
dolphi86 [110]

Answer:

(x+3)(x+2)

Step-by-step explanation:

I can't explain it well, but I call it "reverse foil."  

3 0
3 years ago
Read 2 more answers
F(n)=4n <br> g(n)=n2+2n <br> find f(g(-6))
ELEN [110]

Answer:

When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.

Step-by-step explanation:

To evaluate f(g(-6)), first find g(-6).

g(n) = n² + 2n

Substitute value.

g(-6) = (-6)² + 2(-6)

Square -6. Remember that (-x)² = x²

g(-6) = 36 + 2(-6)

Multiply 2 and -6.

g(-6) = 36 - 12

Subtract 12 from 36.

g(-6) = 24.

Now knowing this, substitute that value into f(n).

f(g(-6)) = f(24)

f(n) = 4n

Substitute value.

f(24) = 4(24)

Multiply 4 and 24.

f(24) = 96.

8 0
2 years ago
Solve the following using Substitution Method. <br> c= 3d - 27<br> 4d + 10c =120
svp [43]

Answer:

d=30-5c/2

Step-by-step explanation:

Move all terms that don't contain d to the right side and solve

8 0
3 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
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